vfio/common: return early if space isn't empty
This is a trivial optimization. If there is active container in space,
vfio_reset_handler will never be unregistered. So revert the check of
space->containers and return early.
Signed-off-by: Zhenzhong Duan <zhenzhong.duan@intel.com>
Reviewed-by: Cédric Le Goater <clg@redhat.com>
Reviewed-by: Eric Auger <eric.auger@redhat.com>
Tested-by: Eric Auger <eric.auger@redhat.com>
Tested-by: Nicolin Chen <nicolinc@nvidia.com>
Signed-off-by: Cédric Le Goater <clg@redhat.com>
diff --git a/hw/vfio/common.c b/hw/vfio/common.c
index 572ae7c..934f4f5 100644
--- a/hw/vfio/common.c
+++ b/hw/vfio/common.c
@@ -1462,10 +1462,13 @@
void vfio_put_address_space(VFIOAddressSpace *space)
{
- if (QLIST_EMPTY(&space->containers)) {
- QLIST_REMOVE(space, list);
- g_free(space);
+ if (!QLIST_EMPTY(&space->containers)) {
+ return;
}
+
+ QLIST_REMOVE(space, list);
+ g_free(space);
+
if (QLIST_EMPTY(&vfio_address_spaces)) {
qemu_unregister_reset(vfio_reset_handler, NULL);
}