exec: hide mr->ram_addr from qemu_get_ram_ptr users
Let users of qemu_get_ram_ptr and qemu_ram_ptr_length pass in an
address that is relative to the MemoryRegion. This basically means
what address_space_translate returns.
Because the semantics of the second parameter change, rename the
function to qemu_map_ram_ptr.
Reviewed-by: Fam Zheng <famz@redhat.com>
Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
diff --git a/include/exec/memory.h b/include/exec/memory.h
index 71a27ab..4ab6800 100644
--- a/include/exec/memory.h
+++ b/include/exec/memory.h
@@ -1393,7 +1393,7 @@
MemoryRegion *mr);
MemTxResult address_space_read_full(AddressSpace *as, hwaddr addr,
MemTxAttrs attrs, uint8_t *buf, int len);
-void *qemu_get_ram_ptr(RAMBlock *ram_block, ram_addr_t addr);
+void *qemu_map_ram_ptr(RAMBlock *ram_block, ram_addr_t addr);
static inline bool memory_access_is_direct(MemoryRegion *mr, bool is_write)
{
@@ -1431,8 +1431,7 @@
l = len;
mr = address_space_translate(as, addr, &addr1, &l, false);
if (len == l && memory_access_is_direct(mr, false)) {
- addr1 += memory_region_get_ram_addr(mr);
- ptr = qemu_get_ram_ptr(mr->ram_block, addr1);
+ ptr = qemu_map_ram_ptr(mr->ram_block, addr1);
memcpy(buf, ptr, len);
} else {
result = address_space_read_continue(as, addr, attrs, buf, len,
